/*
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

 

示例 1：

输入：["h","e","l","l","o"]
输出：["o","l","l","e","h"]

示例 2：

输入：["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

通过次数268,432
提交次数358,926
*/

/*
 * @Author:gxx
 * @QQ : 1278255275
 * @Date: 2021-04-01 15:42:05
 * @Last Modified by: gxx
 * @Last Modified time: 2021-04-01 15:42:05
 * @Description: 翻转字符串
*/

class Solution {
public:
    void reverseString(vector<char>& s) {
        char ch;
        int len = s.size();

            for(int i = 0; i < len/2 ;i++){
                ch = s[i];
                s[i] = s[len-1-i];
                s[len-1-i] = ch;
            }
        cout<<"[";
        for(int i = 0; i < s.size(); i++){
            cout<<"\"";
            cout << s[i];
            cout << "\"";
            if(i != s.size()-1) cout<<",";
        }
        cout<<"]";



    }
};
